Till at 10:55, 19 September 2020

2020-09-19T10:55:24Z

Till: Created page with "The proton is the positively charged particle in the atomic nucleus. This atomic model is based on Rutherford, and Bohr also helped it to triumph over other models. In the n..."

2020-09-19T10:54:37Z

Created page with "The proton is the positively charged particle in the atomic nucleus. This atomic model is based on Rutherford, and Bohr also helped it to triumph over other models. In the n..."

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The proton is the positively charged particle in the atomic nucleus. This atomic model is based on Rutherford, and Bohr also helped it to triumph over other models. In the nucleus there are protons and neutrons whose weight is much greater than that of the electrons that circulate around the nucleus. The proton is currently of interest again. Scientists have allegedly discovered that its radius, namely the charge radius, is smaller than previously assumed. You can find a link here: [http://www.sciencenews.org/view/generic/id/347775/description/Protons_radius_revised_downward Radius des Protons]

Absolute theory does not consider this experiment as conclusive as it has been presented. The radius was not measured with normal hydrogen, but the electron was replaced by a negatively charged muon, which has 200 times the mass of the electron. Now one might say that this mass is still very small. In the sense of the [[mass conservation law]] that mass is not lost and in the sense of [[quantization]], which is also evident in atoms, we can give the stable elements integral ordinal numbers with statistical deviations that correspond to their mass, in In this sense, it is quite possible that if the shell is heavier, the core loses mass and therefore loses its circumference and radius while the density remains the same.

The scientists want to do a second experiment with helium: Here they only want to replace one of the two electrons with the corresponding muon. If the view of the absolute theory were correct, the radius would also be smaller here, but the reduction effect would not be double. Let's see what the scientists then measure for helium.

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-The proton is the positively charged particle in the atomic nucleus.  This atomic model is based on Rutherford, and Bohr also helped it to triumph over other models.  In the nucleus there are protons and neutrons whose weight is much greater than that of the electrons that circulate around the nucleus.  The proton is currently of interest again.  Scientists have allegedly discovered that its radius, namely the charge radius, is smaller than previously assumed.  You can find a link here: [http://www.sciencenews.org/view/generic/id/347775/description/Protons_radius_revised_downward Radius des Protons]
+The proton is the positively charged particle in the atomic nucleus.  This atomic model is based on Rutherford, and Bohr also helped it to triumph over other models.  In the nucleus there are protons and neutrons whose weight is much greater than that of the electrons that circulate around the nucleus.  The proton is currently of interest again.  Scientists have allegedly discovered that its radius, namely the charge radius, is smaller than previously assumed.
- Absolute theory does not consider this experiment as conclusive as it has been presented.  The radius was not measured with normal hydrogen, but the electron was replaced by a negatively charged muon, which has 200 times the mass of the electron.  Now one might say that this mass is still very small.  In the sense of the [[mass conservation law]] that mass is not lost and in the sense of [[quantization]], which is also evident in atoms, we can give the stable elements integral ordinal numbers with statistical deviations that correspond to their mass, in  In this sense, it is quite possible that if the shell is heavier, the core loses mass and therefore loses its circumference and radius while the density remains the same.
+Absolute theory does not consider this experiment as conclusive as it has been presented.  The radius was not measured with normal hydrogen, but the electron was replaced by a negatively charged muon, which has 200 times the mass of the electron.  Now one might say that this mass is still very small.  In the sense of the [[Conservation of mass]] that mass is not lost and in the sense of [[quantization]], which is also evident in atoms, we can give the stable elements integral ordinal numbers with statistical deviations that correspond to their mass, in  In this sense, it is quite possible that if the shell is heavier, the core loses mass and therefore loses its circumference and radius while the density remains the same.
 The scientists want to do a second experiment with helium: Here they only want to replace one of the two electrons with the corresponding muon.  If the view of the absolute theory were correct, the radius would also be smaller here, but the reduction effect would not be double.  Let's see what the scientists then measure for helium.

Proton - Revision history

Till at 10:55, 19 September 2020

Till: Created page with "The proton is the positively charged particle in the atomic nucleus. This atomic model is based on Rutherford, and Bohr also helped it to triumph over other models. In the n..."