Mass and momentum of a photon - Revision history

Till: /* Theory of the mass of the photon */

2020-09-19T11:04:41Z

‎Theory of the mass of the photon

Till: /* Theory of the mass of the photon */

2020-09-19T11:04:33Z

‎Theory of the mass of the photon

Till: /* The proof */

2020-09-19T11:04:05Z

‎The proof

Till: /* Rest mass of the photon */

2020-09-18T16:12:34Z

‎Rest mass of the photon

Till: /* Mass of the photon not defined? */

2020-09-18T16:12:10Z

‎Mass of the photon not defined?

Till: /* Mass of the photon not defined? */

2020-09-18T16:11:51Z

‎Mass of the photon not defined?

Till: /* General */

2020-09-18T16:11:21Z

‎General

Till: /* General */

2020-09-18T16:11:05Z

‎General

Till: /* Theory of the mass of the photon */

2020-09-18T16:10:14Z

‎Theory of the mass of the photon

Till: /* Theory of the mass of the photon */

2020-09-18T16:09:32Z

‎Theory of the mass of the photon

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 == Theory of the mass of the photon ==
-As you can see, Einstein's [[Theory of relativity]] also prescribes a photon mass when calculating the term 0/0 in the mass - rest mass relationship on the various paths.  A photon mass also necessarily follows from [[E = mc²]], since the equation means that total energy and mass are equal and not just equivalent, as Einstein suspected.  And that photons have energy, nobody denies that.  And according to the [[Conservation of mass]] of the absolute theory, the mass of the photon then necessarily follows and not just the momentum and everything becomes clear, uniform and free of contradictions.
+As you can see, Einstein's [[Theory of Relativity]] also prescribes a photon mass when calculating the term 0/0 in the mass - rest mass relationship on the various paths.  A photon mass also necessarily follows from [[E = mc²]], since the equation means that total energy and mass are equal and not just equivalent, as Einstein suspected.  And that photons have energy, nobody denies that.  And according to the [[Conservation of mass]] of the absolute theory, the mass of the photon then necessarily follows and not just the momentum and everything becomes clear, uniform and free of contradictions.
   == Links ==
 @quantenwelt has convinced me that I will not get the paper in a scientific journal, so I am now publishing it here for a small donation: [https://Paypal.me/tillmeyenburg photon mass]

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 == Theory of the mass of the photon ==
-As you can see, Einstein's [[Relativity Theory]] also prescribes a photon mass when calculating the term 0/0 in the mass - rest mass relationship on the various paths.  A photon mass also necessarily follows from [[E = mc²]], since the equation means that total energy and mass are equal and not just equivalent, as Einstein suspected.  And that photons have energy, nobody denies that.  And according to the [[Conservation of mass]] of the absolute theory, the mass of the photon then necessarily follows and not just the momentum and everything becomes clear, uniform and free of contradictions.
+As you can see, Einstein's [[Theory of relativity]] also prescribes a photon mass when calculating the term 0/0 in the mass - rest mass relationship on the various paths.  A photon mass also necessarily follows from [[E = mc²]], since the equation means that total energy and mass are equal and not just equivalent, as Einstein suspected.  And that photons have energy, nobody denies that.  And according to the [[Conservation of mass]] of the absolute theory, the mass of the photon then necessarily follows and not just the momentum and everything becomes clear, uniform and free of contradictions.
   == Links ==
 @quantenwelt has convinced me that I will not get the paper in a scientific journal, so I am now publishing it here for a small donation: [https://Paypal.me/tillmeyenburg photon mass]

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 == The proof ==
-Yes, for the derivation, not everyone believes my new mathematics like under [[Division by Zero]] and [[Complex numbers]], I am forced to prove it with conventional mathematical means.  As shown in the article [[relativistic root]], this can easily be replaced by the velocity v (red) / c, which sweeps over several places.  This is then again equal to the [[time flow]] T (0) / T. So we get: m (photon) = m (0) / v (red) / c or m (photon) = m (0) / (  T (0) / T * c).  According to the unit system, I now leave out c as one, mathematically nothing changes.  Then we look at the term m (photon) = m (0) / [[time flow]].  Depending on v.  For limes (v -> c) the rest mass m (0) decreases until it becomes zero at c according to previous mathematics.  Likewise, the [[time flow]] decreases, things move slower and slower until it becomes zero.  Both functions are strictly monotonically decreasing for limes (v-> c).  For faster than light speed, i.e. limes (v -> infinite), the function goes into the imaginary range, as Einstein and Minkowski prophesy.  Here it would have to either continue to fall or rise, but not contain a turning point in order to be able to apply L'Hospital's theorem.  According to this, the limit value 0/0 is defined when the limit value for a derivative, be it the first or the second, is defined.  For [[faster than light speed]] the rest mass m (0) becomes negative, the [[time flow]] imaginary.  But none of this really helps, today I had the brilliant idea.  And in retrospect, it turns out that the question was never whether a photon has no mass or does.  Einstein's question was, why does the photon have a mass according to [[E = mc²]] if 0 is divided by 0?  I thank the anonymous whistleblower here who referred to L'Hospital's sentence, and my old school friend Schaper, you know him from the inflated crowd and the [[Division by Zero]] who put me on this trail.
+Yes, for the derivation, not everyone believes my new mathematics like under [[Division by Zero]] and [[Complex numbers]], I am forced to prove it with conventional mathematical means.  As shown in the article [[relativistic root]], this can easily be replaced by the velocity v (red) / c, which sweeps over several places.  This is then again equal to the [[time flow]] T (0) / T. So we get: m (photon) = m (0) / v (red) / c or m (photon) = m (0) / (  T (0) / T * c).  According to the unit system, I now leave out c as one, mathematically nothing changes.  Then we look at the term m (photon) = m (0) / [[time flow]].  Depending on v.  For limes (v -> c) the rest mass m (0) decreases until it becomes zero at c according to previous mathematics.  Likewise, the [[time flow]] decreases, things move slower and slower until it becomes zero.  Both functions are strictly monotonically decreasing for limes (v-> c).  For faster than light speed, i.e. limes (v -> infinite), the function goes into the imaginary range, as Einstein and Minkowski prophesy.  Here it would have to either continue to fall or rise, but not contain a turning point in order to be able to apply L'Hospital's theorem.  According to this, the limit value 0/0 is defined when the limit value for a derivative, be it the first or the second, is defined.  For [[faster than light]] the rest mass m (0) becomes negative, the [[time flow]] imaginary.  But none of this really helps, today I had the brilliant idea.  And in retrospect, it turns out that the question was never whether a photon has no mass or does.  Einstein's question was, why does the photon have a mass according to [[E = mc²]] if 0 is divided by 0?  I thank the anonymous whistleblower here who referred to L'Hospital's sentence, and my old school friend Schaper, you know him from the inflated crowd and the [[Division by Zero]] who put me on this trail.
 Ultimately, we square the Einstein mass-rest mass relationship.  Then we have m² = m (0) ² / (1 - v² / c²), because the root falls away below.  Now we derive twice for v, because according to L'Hospital the limit value of 0/0 is given when the derivatives have a limit value.  Below we can see that we get - 2 / c².  So definitely a real number.  For the expression above we then need some physics.  The Einstein energy-momentum equation has to be simplified first.  Then it is called m (0) ² * c ^ 4 + c² * p² = m² * c ^ 4.  That means the rest mass is given by the term m (0) = sqrt (m² - p² / c²).

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 == Rest mass of the photon ==
-Since people on the Internet are now claiming that it was always clear that the photon has mass and that [[Yang-Mill's theory]] was not about that, which, I make it clear, must definitely not be true  I now dig deep into my bag of tricks.  It's about nothing less than proving that the photon also has rest mass.  Ultimately, one does not get any further with the root 0 consideration, since it is equal to 0 according to normal mathematical understanding.  With the [[Division by zero]] and with the [[Complex numbers]] I have shown that calculating with zero still offers surprises.  But we can avoid this problem.
+Since people on the Internet are now claiming that it was always clear that the photon has mass and that [[Yang-Mill's theory]] was not about that, which, I make it clear, must definitely not be true  I now dig deep into my bag of tricks.  It's about nothing less than proving that the photon also has rest mass.  Ultimately, one does not get any further with the root 0 consideration, since it is equal to 0 according to normal mathematical understanding.  With the [[Division by Zero]] and with the [[Complex numbers]] I have shown that calculating with zero still offers surprises.  But we can avoid this problem.
 Ultimately it remains that m_0 = m * root (1 - v² / c²).  But now it is the case that the relativistic root also corresponds to the compared [[time flow]], so T '/ T: T' = T * root (1 - v² / c²) applies.  Now one always claims that time stands still at the speed of light, because here the term becomes the root of 0.  T 'here means the time that has passed in the moving system, in this case of the photon at the speed of light.

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 == Mass of the photon not defined?  ==
-It used to be said that the photon has an undefined mass, since it is divided by zero according to the connection between mass and rest mass.  m = m (0) / relativistic root.  Since both tends towards zero for the photon or becomes zero, it was assumed that the mass of the photon was not defined.  But that you can define the [[Division by Zero]], you can read here under [[Division by Zero]].  One could also say, if one disregards this, that the limit value tends towards zero, but the term becomes 1, which corresponds to the [[elementary mass]].  This is due to the fact that both the rest mass and the relativistic root tend towards zero and this evenly.  It is a mystery to me why this question is ignored in recent literature and why it is claimed per se that the photon has no mass.  The answer to this question is not that simple.
+It used to be said that the photon has an undefined mass, since it is divided by zero according to the connection between mass and rest mass.  m = m (0) / relativistic root.  Since both tends towards zero for the photon or becomes zero, it was assumed that the mass of the photon was not defined.  But that you can define the [[Division by Zero]], you can read here under [[Division by Zero]].  One could also say, if one disregards this, that the limit value tends towards zero, but the term becomes 1, which corresponds to the [[elemental mass]].  This is due to the fact that both the rest mass and the relativistic root tend towards zero and this evenly.  It is a mystery to me why this question is ignored in recent literature and why it is claimed per se that the photon has no mass.  The answer to this question is not that simple.
 == Photon and Gravitation ==

@@ Line 1: / Line 1: @@
 == General ==
-The photon has a mass from the [[Conservation of mass]], even if it has no rest mass according to Einstein.  Accordingly, according to the [[equivalence of space and time]], mass and momentum are equivalent.  So a photon also has an impulse.  This corresponds to the [[elementary mass]] multiplied by the speed of light.  This applies to the elementary frequency.  Otherwise one can calculate the mass of a photon with m = h * f / c².  Learning without frustration and the University of Ulm have calculated this based on this equation, which I have always fought for, and arrive at a value for an average photon of:
+The photon has a mass from the [[Conservation of mass]], even if it has no rest mass according to Einstein.  Accordingly, according to the [[equivalence of space and time]], mass and momentum are equivalent.  So a photon also has an impulse.  This corresponds to the [[elemental mass]] multiplied by the speed of light.  This applies to the elementary frequency.  Otherwise one can calculate the mass of a photon with m = h * f / c².  Learning without frustration and the University of Ulm have calculated this based on this equation, which I have always fought for, and arrive at a value for an average photon of:
   m (photon) = 10 ^ -36 kg

← Older revision		Revision as of 16:09, 18 September 2020
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	== Links ==		== Links ==
−	~~The~~ @quantenwelt has convinced me that I will not get the paper in a scientific journal, so I am now publishing it here for a small donation: [https://Paypal.me/tillmeyenburg photon mass]	+	@quantenwelt has convinced me that I will not get the paper in a scientific journal, so I am now publishing it here for a small donation: [https://Paypal.me/tillmeyenburg photon mass]